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0=1.3x^2+3.9x
We move all terms to the left:
0-(1.3x^2+3.9x)=0
We add all the numbers together, and all the variables
-(1.3x^2+3.9x)=0
We get rid of parentheses
-1.3x^2-3.9x=0
a = -1.3; b = -3.9; c = 0;
Δ = b2-4ac
Δ = -3.92-4·(-1.3)·0
Δ = 15.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.9)-\sqrt{15.21}}{2*-1.3}=\frac{3.9-\sqrt{15.21}}{-2.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.9)+\sqrt{15.21}}{2*-1.3}=\frac{3.9+\sqrt{15.21}}{-2.6} $
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